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Match the function with the correct scenario. 1 (t) = 9000 (1 +0.066) 2. g(t)= 9000 (1+0.006) The value of a loan of $9,000 at

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Match the function with the correct scenario. 1 (t) = 9000 (1 +0.066) 2. g(t)= 9000 (1+0.006) The value of a loan of $9,000 at 6% annual interest after t years. The amount of interest accrued on a $9,000 loan with 0.6% interest after t years. The amount of interest accrued on a $9,000 loan with 6% interest after t years. The value of a loan of $9.000 at 0.6% annual interest after t years. 3. h(t) = 9000. 0.06. 4. k (t) = 9000 -0.006 - t

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