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mean = 960. Standard deviation = 6.5 i) What is the percent of cans with volume above 960 mL ( find the percentage of cans

mean = 960. Standard deviation = 6.5

i) What is the percent of cans with volume above 960 mL ( find the percentage of cans with a volume of at least 960 ml).

ii)What is the percentage of cans whose volume is between 950 mL and 960 mL.

iii) Below what volume are the bottom 40% of volumes of cans of primer. Recall that this volume is the 40th percentile for the volume of primer.

iv) Above what volume is/are the top 10% of volumes among cans of primer?

v) If a can contains no more than 945 mL of paint, it is rejected by the quality control board. That is, acan is rejected by the quality control department if it contains less than 945 mL. What percentage of cans are to be rejected?

vi) A can is rejected by the quality control department if it contains less than 945 mL. Compute the probability of at least one rejection among a random sample of 13 cans of paint.

Please explain step by step I am so confused

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