Meth Bus (385:02) Exam #2 04/05/23 The residuals for 10 consecutive time periods are given in the following table. Time Period Residual 1 2 3 4 5 6 -1 +6 +5 +9 -1 7 8 -1 +4 +9 9 10 -7 +9 < Question 5 of 9 > This test: 29 point(s) possible This question: 3 point(s) possible Submit test a. Plot the residuals over time. What conclusion can you reach about the pattern of the residuals over time? b. Based on (a), what conclusion can you reach about the autocorrelation of the residuals? a. Plot the residuals over time. Choose the correct graph below. A. 10- 0- | -10+ 0 Time Period Q B. 10- -10+ 0 Time Period What conclusion can you reach about the pattern of the residuals over time? A. A decreasing linear relationship exists. B. No linear relationship exists. C. An increasing linear relationship exists. b. Based on (a), what conclusion can you reach about the autocorrelation of the residuals? A. There appears to be a strong negative autocorrelation among the residuals. B. There appears to be a strong positive autocorrelation among the residuals. C. There does not appear to be an autocorrelation among the residuals. 0 . Residuals 10+ 0- -10+ 0 Time Period 10 D. Residuals 10+ 0- -10+ 0 10 Time Period Meth Bus (385:02) Exam #2 04/05/23 Question 6 of 9 > This test: 29 point(s) possible This question: 2 point(s) possible If the Kruskal-Wallis rank test for comparing the medians is used in seven populations at the 0.05 level of significance, the upper-tail critical value from the chi-square distribution is 12.592. Complete parts (a) and (b) below. a. State the decision rule for testing the null hypothesis that all seven groups have equal population medians. Let H be the Kruskal-Wallis test statistic. Choose the correct answer below. A. Reject Ho if H> -12.592 and H < 12.592; otherwise, do not reject Ho B. Reject Ho if H 12.592; otherwise, do not reject Ho D. Reject Ho if H < -12.592 or if H> 12.592; otherwise, do not reject Ho. b. What is the statistical decision if the computed value of the test statistic H is 9.14? Ho because H = 9.14 Submit test Meth Bus (385:02) Exam #2 04/05/23 Question 4 of 9 The ANOVA summary table for an experiment with four groups, with six values in each group, is shown to the right. Complete parts (a) through (d) below. This test: 29 point(s) possible This question: 4 point(s) possible Source Among groups Within Degrees of Freedom c-1 3 Click here to view page 1 of the F table. Click here to view page 2 of the F table. Click here to view page 3 of the F table. Click here to view page 4 of the F table. a. At the 0.05 level of significance, state the decision rule for testing the null hypothesis that all four groups have equal population means. Determine the hypotheses. Choose the correct answer below. OA. Ho: H =H = ="6 H: * * # H6 OC. Ho H==P4 H: # * # H4 Find the test statistic. F STAT (Round to two decimal places as needed.) Determine the critical value. F = (Round to two decimal places as needed.) b. What is your statistical decision? Ho. There is evidence to conclude that there is a difference in the population means of the groups. c. At the 0.05 level of significance, what is the upper-tail critical value from the Studentized range distribution? Q = (Round to two decimal places as needed.) d. To perform the Tukey-Kramer procedure, what is the critical range? Critical range = (Round to three decimal places as needed.) OB. Ho H=4 H: Not all the means are equal. OD. Ho H = = H6 H: Not all the means are equal. Submit test Sum of Mean Squares Square (Variance) F SSA=180 MSA=60 FSTAT = 2.00 n-c=20 SSW=600 MSW = 30 groups Total n-1 23 SST=780 Time Remaining: 01:17:55