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Modify the following cubic spline MATLAB code into quadratic spline. Do NOT use AI for this task. Clearly explain your reasoning with necessary equations. Also

Modify the following cubic spline MATLAB code into quadratic spline. Do NOT use AI for this task. Clearly explain your reasoning with necessary equations. Also provide an example plot at the end of the code. Thank you!
function yy = natspline(x, y, xx)
% natspline(x,y,xx):
% uses a natural cubic spline interpolation to find yy, the values
% of the underlying function y at the points in the vector xx.
% The vector x specifies the points at which the data y is given.
n = length(x);
m = length(xx);
aa = zeros(n);
bb = zeros(n,1);
% Boundary conditions for natural spline
aa(1,1)=1;
aa(n, n)=1;
bb(1)=0;
bb(n)=0;
% Build the system of equations
for i =2:n-1
aa(i, i-1)= h(x, i -1);
aa(i, i)=2*(h(x, i -1)+ h(x, i));
aa(i, i+1)= h(x, i);
bb(i)=3*(fd(i +1, i, x, y)- fd(i, i -1, x, y));
end
% Solve for c
c = aa \ bb;
% Calculate spline coefficients a, b, d
a = y(1:n-1)';
b = zeros(n-1,1);
d = zeros(n-1,1);
for i =1:n-1
b(i)= fd(i +1, i, x, y)- h(x, i)/3*(2* c(i)+ c(i +1));
d(i)=(c(i +1)- c(i))/3/ h(x, i);
end
% Evaluate the spline at the points in xx
yy = zeros(m,1);
for i =1:m
yy(i)= SplineInterp(x, n, a, b, c, d, xx(i));
end
end
% Helper function to calculate intervals
function hh = h(x, i)
hh = x(i +1)- x(i);
end
% Helper function to calculate finite differences
function fdd = fd(i, j, x, y)
fdd =(y(i)- y(j))/(x(i)- x(j));
end
% Helper function for spline interpolation
function yyy = SplineInterp(x, n, a, b, c, d, xi)
for ii =1:n-1
if xi >= x(ii)-0.000001 && xi <= x(ii +1)+0.000001
yyy = a(ii)+ b(ii)*(xi - x(ii))+ c(ii)*(xi - x(ii))^2+ d(ii)*(xi - x(ii))^3;
break;
end
end
end

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