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Molecular hydrogen (H 2 ) is heated in a nuclear rocket chamber to a temperature of 3000 K. The equilibrium constant for the hydrogen dissociation
Molecular hydrogen (H2) is heated in a nuclear rocket chamber to a temperature of 3000 K. The equilibrium constant for the hydrogen dissociation reaction H2 -> 2H at this temperature is Kp=(PH)2 / (PH2) = 0.03; where P is in atmospheres. If the chamber pressure is 10 atm, calculate the mole fractions of H2 and H.
This is a propulsion question, please only answer if you know what you're doing
Molecular hydrogen (H2) is heated in a nuclear rocket chamber to a temperature of 3000K. The equilibrium constant for the hydrogen dissociation reaction H22H at this temperature is Kp=(pH)2/(pH2)=0.03, where p is in atmospheres. If the chamber pressure is 10atm, calculate the mole fractions of H2 and HStep by Step Solution
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