My question is specifically about part B of this question. I have calculated that the probability in part A is 0.0123. But pertaining to part B, does this mean that more than 48% of customers express delight? If so, why? This was all the information that was given.

Quality Progress reports on improvements in customer satisfaction and loyalty made by Bank of America. A key measure of customer satisfaction is the response {on a scale from 1 to 1D} to the question: "Considering all the business you do with Bank of America. what is your overall satisfaction with Bank of America?" Here. a response of 9 or 1D represents "customer delight." Historically. the percentage of Bank of America customers expressing customer delight has been 43%. Suppose that we wish to use the results of a survey of 350 Bank of America customers to justify the claim that more than 43% of all current Bank of America customers would express customer delight. The survey nds that 139 of 350 randomly selected Bank of America customers express customer delight. If, for the sake of argument. we assume that the proportion of customer delight is p = .43. calculate the probability of observing a sample proportion greater than or equal to 139r'350 a = .54. That is. calculate H? a 54). Based on the probability you computed in part a, would you conclude that more than 43 percent of current Bank of America b customers express customer delight? Explain.