my text at the bottom "splving for" is at the centre but id like to be at the left : $\begin{align} x^*_k&= \frac{27\mu (x^*_k)^2 (1-x^*_k)}{16} \\[5pt] \implies 27 \mu (x^*_k)^2(1-x^*_k)-16x^*_k&=0 \\[5pt] &=27 \mu (x^*_k)^2 -27 \mu(x^*_k)^3 -16x^*_k & \\[5pt] &=x^*_1[-27 \mu(x^*_{2,3})+27 \mu(x^*_{2,3})-16], \\[5pt] \\[5pt] \text{which implies that} \space \\[5pt] x^*_1&=0,\\[5pt] \text{and that}\\[5pt] (x^*_{2,3})^2-(x^*_{2,3})+\frac{16}{27 \mu}&=0.\\[15pt] \\[5pt] \text{Solving for} \space x^*_{2} \text{and} \space x^*_{3}: \\[5pt] \end{align}$