$N{O}_2(g)NO(g)+\frac{1}{2}{O}_2(g)$

is second order in $N{O}_2$ with a rate constant of $0\mathrm{.}540\frac{1}{M*s}.$

If the initial concentration of $N{O}_2$ is $0\mathrm{.}0588M,$ the concentration of $N{O}_2$ will be $M$ after $108$ seconds have passed.

$6$ more group attempts remaining