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Consider the following two equations: (3) 3Ca2+(aq)+2PO42(aq)=Ca3(PO4)2(s) (4) PO43(aq)3+nH3O(aq)+HnPO4n3(aq)+nH2O(l) If you added HCl (a source of H3O+) to a test tube containing Ca3(PO4)2, Equation 4 would shift to the which would the concentration of phosphate ions in solution. Equation 3 would then shift to the causing right; decrease; right; Ca3(PO4)2 to dissolve right; increase; right; more Ca3(PO4)2 to form right; decrease; left; Ca3(PO4)2 to dissolve left; increase; right; more Ca3(PO4)2 to form right; decrease; right; more Ca3(PO4)2 to form