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The 2 Sample Z Test

An ABC News/Washington Post poll asked 374 randomly selected adults aged 18-29 and 1,001 randomly selected adults of all ages 'Do you think it should be legal or illegal for gay and lesbian couples to get married?' 81% of adults aged 18-29 favored legalization compared to 58% of adults across all ages, a difference of 23%. To compute the likelihood that you'd see such a difference or more just due to the luck of the draw, you first need to calculate the SE of the 2 samples.

In the young adult poll 81% favored gay marriage; the SE for this percentage is (Hint: first compute the SD of the box by estimating it to have 81% 1's)2.0300%

You are correct. Your receipt no. is 156-486

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In the all adult poll 58% favored gay marriage; the SE for this percentage is1.5600%

You are correct. Your receipt no. is 156-8805

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The difference is 23%; the SE for this difference is%

Incorrect.

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What is the value of the test statistic z?

Incorrect.

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What is the value of the p-value? (If the z value is off the chart, assume the middle are is at least 99.9996%

Incorrect.

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Should you reject the null hypothesis, that the difference is due to chance?

Yes, doesn't look like the difference could be due to chance.

No, it looks like the difference could easily be explained by chance.

Chi-Square Test for Independence

Last semester Survey 1 asked students whether they were right-handed, left-handed or ambidextrous. Suppose we wanted to compare handedness between men and women.

To test the null hypothesis that there's no difference in handedness between men and women, what significance test should we use?

the Chi-Square-test for Independence

the two-sample z-test

the one-sample z-test

Chi-Square Goodness-of-fit test

Incorrect.

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Suppose the table below shows the responses of 617 people who filled out survey 1.

Compute how many you would expect in each category if men and women were really the same in terms of handedness.

Observed Frequencies

163	17	17	197
381	30	9	420
544	47	26	617

Fill in the 6 cells below.(Give your answers to 2 decimal places.)

Table of Expected Frequencies

Incorrect.

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Fill in the 3 missing terms in the equation below. The first 3 terms correspond to the first row (the males), fill in the terms for the second row (the females) in the correct order reading from left to right.(The observed frequencies for the females are 381, 30, and 9. You just computed the expected frequencies for the females in the table above.)

The chi-square statistic is the sum of 6 terms = (Round your answers to 2 decimal places.)

0.66 + 0.26 + 9.11 +? +?+?

In a past survey 658 students responded anonymously to the controversial question: There are 2 ways to place a roll of toilet paper on a horizontal holder as illustrated in the diagram below:

Which method do you believe is best? Under, Over or Don't Care

Suppose we want to test the null hypothesis that the difference in responses between the 232 males and the 426 females is just due to chance and we want to include all 3 categories ("under", "over" and "don't care"). (Even though the surveys weren't really random samples, imagine that they were randomly drawn from a large population of typical Stat 100 students.)

a. What significance test should we use?

the one-sample z-test the two-sample z-test the Chi-Square Goodness-of-fit test the Chi-Square-test for Independence

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Here are the Observed Frequencies. Fill in the bottom row with the correct totals.

51	154	27	232
101	300	25	426
658

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