NO reacts in the presence of H2 to form N2O according to the following reaction mechanism where N2O2 is a highly reactive intermediate. 2NOk1N2O2N2O2+H2k2N2O+H2O Show that the rate law for formation of N2O expected on the basis of this mechanism is: dtdpN,0=k1+k2pIIk1k2(pNo)2p11 where pN2,,pNo and pIH, are the partial pressures of N2O,NO and H2, respectively. Predict the limiting forms of the rate equation at high and low initial H2 pressures and identify the rate-limiting step in each case