Non-Concurrent Forces Boom ID: 3 Boom length (cm): 25.82 Boom mass (g): 39.56 Table 1: Determination of Boom's Reaction Force R's mass equivalent Force Load Angle Protractor angleAngle wrt to x axis x-comp y-comp Symbol (g) Symbol ( 0 ) + 20 (x-axis) (") (g) (g) Measured W 55 50 230 -35.4 -42.1 T 105 V 66 114 -42.7 95.9 WB 39.56 a 50 230 -25.4 -30.3 Calculated R 106.1 Bcalculated 52.8 -12.8 103.5 -23.5 Table 2: Vector Board Measurements. Force Load Angle Vector Board Symbol g) Symbol Angle () +20 W 55 OL 52 T 105 67 WB 39.56 OL 52 R 106 Pmeasured 11C T Pulley B Tie Mast String clamp D Boom B R W, A WB (a) (b) Figure 1: (a) The model derrick (b) A free-body diagram of the boom.Boom Overall L Piv to Cbl Cbl to Ld Mass Number cm cm cm 3.00 25.82 14.98 25.03 39.565. Calculate the torque exerted by each force around the point where the boom attaches to the mast. (Note: the total value, the net torque from adding up each individual torque, should be close to 0 Nm, but will probably not be exactly 0 due to uncertainty). (hint: the second sheet in ST2_Data contains data on location of string attachments for each boom) (3 pt) 6. In the vector board measurements, it is important to ensure that the boom is not up against the edge of the metal loop. Explain why this is needed for the experiment (1 pt)