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On the interval 0 to 1, what is the square modulus (in terms of a and b) of the trial wave function in eq. 6-15?
On the interval 0 to 1, what is the square modulus (in terms of a and b) of the trial wave function in eq. 6-15?
(x;a,b) = x(1-x) (6-15)
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To find the square modulus of the trial wave function xix a b on the interval 0 1 we can ...
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Differential Equations And Linear Algebra
Authors: C. Edwards, David Penney, David Calvis
4th Edition
013449718X, 978-0134497181
