Question
One mole of an ideal gas with C P = (5/2) R and C V = (3/2) R expands from P 1 = 6 bar
One mole of an ideal gas with CP = (5/2)R and CV = (3/2)R expands from P1 = 6 bar and T1 = 820 K to P2 = 1 bar.
Take the value of R to be 8.314 J·mol−1·k−1.
At constant volume (assume mechanical reversibility), find the value of W, Q, ΔU, and ΔH? (Include a minus sign if required.)
Step by Step Solution
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Step: 1
Answer Using the ideal gas law PVnRTPVnRT we can find the initial volume V1V1 V1nRT1P1V1...
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Introduction to Chemical Engineering Thermodynamics
Authors: J. M. Smith, H. C. Van Ness, M. M. Abbott
7th edition
71247084, 978-0071247085
