OptiLux is considering investing in an automated manufacturing system. The system requires an initial investment of $6.0 million, has a 20-year life, and will have zero salvage value. If the system is implemented, the company will save $900,000 per year in direct labor costs. The company requires a 12% return from its investments. (PV of $1, FV of $1, PVA of $1, and FVA of $1) (Use appropriate factor(s) from the tables provided.) a. Compute the proposed investment's net present value. b. Using the answer from part a, is the investment's internal rate of return higher or lower than 12%? Complete this question by entering your answers in the tabs below. Required A Required B Compute the proposed investment's net present value. Net present value Table B.1* Present Value of 1 p=1/(1+1)" 12% Rate Periods 1% 2% 3% 4% 5% 6% 7% 8% 9% 10% 15% Periods 1 0.9901 0.9804 0.9709 0.9615 0.9524 0.9434 0.9346 0.9259 0.9174 0.9091 0.8929 0.8696 1 2 0.9803 0.9612 0.9426 0.9246 0.9070 0.8%) 0.8734 0.8573 0.8417 0.8264 0.7972 0.7561 2 3 0.9706 0.9423 0.9151 0.889) 0.8638 0.8396 0.8163 0.7938 0.7722 0.7513 0.7118 0.6575 3 4 0.9610 0.9238 0.8885 0.8548 0.8227 0.7921 0.7629 0.7350 0.7084 0.6830 0.6355 0.5718 4 5 0.9515 0.9057 0.8626 0.8219 0.7835 0.7473 0.7130 0.6806 0.6499 0.6209 0.5674 0.4972 5 6 0.9420 0.8880 0.8375 0.7903 0.7462 0.7050 0.6663 0.6302 0.5963 0.5645 0.5066 0.4323 6 7 0.9327 0.8706 0.8131 0.7599 0.7107 0.6651 0.6227 0.5835 0.5470 0.5132 0.4523 0.3759 7 8 0.9235 0.8535 0.7894 0.7307 0.6768 0.6274 0.5820 0.5403 0.5019 0.4665 0.4039 0.3269 8 9 0.9143 0.8368 0.7664 0.7026 0.6446 0.5919 0.5439 0.5002 0.4604 0.4241 0.3606 0.2843 9 10 0.9053 0.8203 0.7441 0.6756 0.6139 0.5584 0.5083 0.4632 0.4224 0.3855 0.3220 0.2472 10 11 0.8963 0.8043 0.7224 0.6496 0.5847 0.5268 0.4751 0.4289 0.3875 0.3505 0.2875 0.2149 11 12 0.8874 0.7885 0.7014 0.6246 0.5568 0.4970 0.4440 0.3971 0.35SS 0.3186 0.2567 0.1869 12 13 0.8787 0.7730 0.6810 0.6006 0.5303 0.4688 0.4150 0.3677 0.3262 0.2897 0.2292 0.1625 13 14 0.8700 0.7579 0.6611 0.5775 0.5051 0.4423 0.3878 0.3405 0.2992 0.2633 0.2046 0.1413 14 15 0.8613 0.7430 0.6419 0.5552 0.4810 0.4173 0.3624 0.3152 0.2745 0.2394 0.1827 0.1229 15 16 0.8528 0.7284 0.6232 0.5339 0.4581 0.3936 0.3387 0.2919 0.2519 0.2176 0.1631 0.1069 16 17 0.8444 0.7142 0.6050 0.5134 0.4363 0.3714 0.3166 0.2703 0.2311 0.1978 0.1456 0.0929 18 0.8360 0.7002 0.5874 0.4936 0.4155 0.3503 0.2959 0.2502 0.2120 0.1799 0.1300 0.0808 18 19 0.8277 0.6864 0.5703 0.4746 0.3957 0.3305 0.2765 0.2317 0.1945 0.1635 0.1161 0.0703 19 20 0.8195 0,6730 0.5537 0.4564 0.3769 0.3118 0.2584 0.2145 0.1784 0.1486 0.1037 0.0611 20 25 0.7798 0.6095 0.4776 0.3751 0.2953 0.2330 0.1842 0.1460) 0.1160 0.0923 0.0588 0.0304 25 30 0.7419 0.5521 0.4120 0.308 0.2314 0.1741 0.1314 0.0994 0.0754 0.0573 0.0334 0.0151 30 35 0.7059 0.5000 0.3554 0.2534 0.1813 0.1301 0.0937 0.0676 0.0490 0.0356 0.0189 0.0075 35 40 0.6717 0.4529 0.3066 0,2083 0.1420 0.0972 0.0668 0.0460 0.0318 0.0221 0.0107 0.0037 40 *Used to compute the present value of a known future amount. For example: How much would you need to invest today at 10% compounded semiannually to accumulate $5,000 in 6 years from today? Using the factors of n = 12 and i = 5% (12 semiannual periods and a semiannual rate of 5%), the factor is 0.5568. You would need to invest $2,784 today ($5,000 x 0.5568)