Options for P(A): 7.02%, 24.59%, 26.5%, 42.16%

Options for P(B): 0.52%, 5.29%, 7.2%, 10.07%

Options for P(O): 33.15%, 43.96%, 66.3%, 81.42%

Options for P(AB): 1.91%, 3.82%, 29.88%, 33.7%

Humans are split into four blood type groups based on the ABO model. In this model, the relationships between genotypes and phenotypes are as displayed in the table below. Let's say we know that the marginal frequencies for each allele are a: 26.5%, b: 7.2%, and o: 66.3%. Assuming independent inheritance of alleles, what are the expected blood type frequencies? That is, P(a) = .265, P(b) = 0.072, and P(o) = 0.663. Here we use capital letters to refer to the blood types and lower case to refer to the alleles; note that P(A) DOES NOT necessarily equal P(a), etc. Keep in mind that the sum of frequencies must equal 1. Hint: Think of the possible ways to get each genotype. You can model this problem as rolling a pair of weighted three-sided dice. BI cl t 00 ype Genotypes Expected probability (phenotype) A 2a,1a&1 P(A)= 7.02% V o B 2b,1b&1 P(B)= 0.52% V o O 2 O P(O) = 43.96% V AB 1 a & 1 b P(AB) = 191% V