part 3 please

The Taylor series formula is f (a ) + f' ( a ) ( x - a ) + f (@) ( x - 2) 2 + f ." (a ) ( x - a) 3 + 1(#) ( a ) ( x - a ) 4 + ... . 2! 3 ! The function, f(x) = 3 cos x has derivatives f' ( x ) = -3 sin (x) -3 sin x f " ( x ) = -3 cos (x) -3 cos f "" ( x ) = 3 sin (x) 3 sin a and (4) (x) = 3 cos (x) 3 coS _ Part 2 of 4 With a = 9x, f(9n) = -3 - 3 , f'(97) = 0 0 , f" ( 97 ) = 3 0 3 f " (9) = 0 0 , and ((4) (9 ) = -3 -3 Part 3 of 4 Therefore, the Taylor Series begins (x - 97) + 2 ! (X - 9T) 2 + 3 ! -(X - 97) 3 + 4! ( x - 97) 4 + .... Submit Skip (you cannot come back)