Part B. Got a crazy answer what did I do wrong?

b. Assuming that 3.774kg of NaCl (Hint: NaCl is a strong electrolyte) is distributed across a roadway, at what temperature is the road going to freeze in a winter storm? For the purposes of measuring water volume on the road surface, assume we are examining a 0.58km stretch of road that is 15.5 meters wide with a 2.50mm layer of water on top. Kf=1.86Ckg/mol, density =0.997g/cm3. Show your work. (4/6 points ) Moles of NaCl : (3.774kg)(1000)=3774g58.44molgNaCl3774gNaCl=64.57905544mol Volume of Water: .58km(1000m)=580m1000m2.50mm=.0025m(580)(15.5)(.0025)=22.475mm3/(100cm3)=.022475cm3 Mass of water: 0.997cm3g=.022475cm3x=.022407575g1000kg.022407575g=2.2407575105kg Molality: 2.2407575105kg64.57905544mol=2882018.935molar Final: j=2(i)(1.86)(2882018.935)=10721110.440C(10721110.44)=10721110.44C