Part I: HEAT OF FUSION

DATA PAGEFOR THE HEAT OF FUSION LAB

Question 1:In order for the ice cube to melt, it has to extract heat energy from the warmer water, first a small amount of heat to warm up to 0C, then a larger amount to melt. The melting ice absorbs heat energy, and thus cools the water. The heat energy absorbed per gram when a substance changes from a solid to a liquid is called the heat of fusion. How is the amount of heat energy absorbed by the solid related to the heat of fusion and the mass of the solid?

Question 2:The total amount of heat energy lost by the water is equal to the amounts of heat energy it took to do what things?

Question 3:What are some sources of error in this experiment?

Part II: HEAT MIXES

Measuring Heat Lab

Data:(Remember to write correct units!!)

Results:

1. Calculate the heat lostbythe hot water.Rememberto writetheunits!!

Qforhot material

Q=m x(Ti- Tf)xCp

Q = Jouls

3. Calculatethe heatgained bythecold water. Rememberto writetheunits!!

Qforcold material

Q=m x(Tf-Ti) xCp

Q= Jouls

Question 4:What is the difference (in Joules) in the amount of heat lost by the hot material and the amount of heat

gained by the cold material?

Question 5:How do you explain any differences? In other words, this amount of heat did not get transferred from the hot water to the cold water. What happened to it

Question 6:Suppose you were to drop a very hot quarter into a cup of cold water. Describe the energy transfer that would take place.

Sample

1. Calculate the heat lostbythe hot water.Rememberto writetheunits!!

Qforhot material

Q=m x(Ti- Tf)xCp

Q = 0.09650 kgx(85.0-54.0) Cx4186J/kgC

Q = 0.09650 kgx31 Cx4186J/kgC

Q = 12,500 Jouls

3. Calculatethe heatgained bythecold water .Rememberto writetheunits!!

Qforcold material

Q=m x(Tf-Ti) xCp

Q = 0.09818 gx(54.0-25.0) Cx4.184J/gC

Q = 0.09818 gx29 Cx4.184J/gC

Q = 11,900 Jouls

1. What isthedifference (inJoules) in theamountofheat lostbythe hotwaterandtheamountofheat gained bythe coldwater?

The hotwater lost 600 Jmore than thecoldwater gained.

1. Howdo you explain any differences?In other words, thisamountofheatdid not get transferred fromthe hot watertothecold water.Whathappened toit?If hotwaterisgreater, than notallthe

heatwent intothe coldwater. Someescapedinto air.If coldwaterisgreater, than allowed

hotwaterto coolbefore pouringinto coldwater,soinitial tempofhotwaterwaslower.

3.Suppose you wereto drop avery hotquarter intoa cup of cold water. Describe theenergytransfer that would takeplace.