( PICTURE ADDED AT BOTTOM TO HELP WITH CLARIFICATION OF THE CHART, THANK YOU!)

A developmental psychologist hypothesizes that drinking fruit juice effects the aggression of children. Children in the experimental condition were given a can of fruit juice during their afternoon break. Children in the control condition were not given any fruit juice. The aggression of the children was measured after the break. Answer the questions below using the partial results.

		N	Mean	Std. Deviation	Std. Error Mean
aggression	experimental	13		6.9385	1.9244
control	13		7.1932	1.9950

		Levene's Test for Equality of Variances	t-test for Equality of Means
		F	Sig.	t	df	Sig. (2-tailed)	Mean Difference	Std. Error Difference	95% Confidence Interval of the Difference
Lower	Upper
aggression	Equal variances assumed	5.484	0.220				-3.1200

a) Compute the appropriate test statistic(s) to make a decision about H₀. Test Statistic = _____ ; ?

Decision: ---Select ONE--- Reject H0, Fail to reject H0 b) If appropriate, compute the CI. If not appropriate, input "na" for both spaces below. [ _____ , _____ ] c) Compute the corresponding effect size(s) and indicate magnitude(s). If not appropriate, input and/or select "na" below. d = _____ ;

Magnitude: ---Select ONE--- na, trivial effect, small effect, medium effect, large effect d) Make an interpretation based on the results (CHOOSE ONE): -Children that did not drink fruit juice were significantly less aggressive than those that did.

-Drinking fruit juice significantly decreases the aggression of children.

-Drinking fruit juice does not have a significant effect on the aggression of children.

A developmental psychologist hypothesizes that drinking fruit juice effects the aggression of children. Children in the experimental condition were given a can of fruit juice during their afternoon break. Children in the control condition were not given any fruit juice. The aggression of the children was measured after the break. Answer the questions below using the partial results. N Mear Std. Deviation Std. Error Mean aggression experimental 13 6.9385 1.9244 control 13 7.1932 1.9950 Levene's Test for Equality of Variances t-test for Equality of Means 95% Confidence Interval of the Difference F Sig. df Sig. (2-tailed) |Mean Difference | Std. Error Difference Lower Upper aggression Equal variances assumed 5.484 0.220 -3.1200 a) Compute the appropriate test statistic(s) to make a decision about Ho- Test Statistic = Decision: [-Select-- b) If appropriate, compute the CI. If not appropriate, input "na" for both spaces below. c) Compute the corresponding effect size(s) and indicate magnitude(s). If not appropriate, input and/or select "na" below. d = ;Magnitude: -Select-- d) Make an interpretation based on the results. O Children that did not drink fruit juice were significantly less aggressive than those that did. Drinking fruit juice significantly decreases the aggression of children. O Drinking fruit juice does not have a significant effect on the aggression of children