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Please explain! Problem 2: By finding an antiderivative, evaluate the following integral, where the path is an arbitrary contour between the indicated limits of integration:

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Problem 2: By finding an antiderivative, evaluate the following integral, where the path is an arbitrary contour between the indicated limits of integration: (a) ze2z dz. J 2i (b) .2Ti z cos z dz; Jo (c) sin z e2 cos = dz

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