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A real estate broker wants to analyze the real estate prices in the GTA. She took a random sample of 40 houses in Richmond Hill and another random sample of 33 houses in Mississauga. The sample means (in $ thousands) are a1 = 497 for Richmond Hill and 2 = 464 for Mississauga. The population standard deviations are o1 = 93.6 for Richmond Hill and o2 = 76.2 for Mississauga. Can she claim at a 3% significance level that the average price in Richmond Hill is higher than the average price in Mississauga? Use the z-test for independent samples and the formula, (51 - 2) - (141 - 12) Zst + n1 n2 (a) State the null and alternative hypotheses, and identify which one is the claim. Ho: Select an answer v ? v H1: Select an answer v ? v Which one is the claim: OH1 OHoFor parts (b), (c) use the correct sign for the z-value (from the z-score table) and test statistic, and round your answers to 3 decimal places as appropriate. (b) What is the critical z-value? :] (c) What is the test statistic? :] (d) Is the null hypothesis rejected? 0 No 0 Yes (e) Is the claim supported? 0 No, there is not sufficient evidence to support the claim that the average price in Richmond Hill is higher than the average price in Mississauga. 0 Yes, there is sufficient evidence to support the claim that the average price in Richmond Hill is higher than the average price in Mississauga. > Next