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Please help me check my math; The length of a rectangle is 3 cm more than twice its width. If the perimeter of the rectangle
Please help me check my math;
The length of a rectangle is 3 cm more than twice its width. If the perimeter of the rectangle is 66 cm, find the length of the rectangle.
So, x = width so 2x+3 = length.
The equation I got was;
2x +2(2x+3)=66
I solved for x and got 10. So, in order to find the length and the answer to the problem, it's 2(10)+3? Which is 23.
So width is 10, and the length is 23? Did I do that correctly? 23(2)+10(2)=66. The wording of the problem confuses me greatly.
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