Please help me verify if these answers are correct for this problem. I am not sure if I did correct. Thank you.

A retailer receives shipments of batteries in packages of 50. The retailer randomly samples 400 packages and tests to see iii of Defective Frequency of D1 if the batteries are defective. A sample of 400 packages revealed the observed frequencies shown to the right. The retailer Batteries per Package Occurrence would like to know if it can evaluate this sampling plan using a binomial distribution with n = 50 and p = 0.02. Test at the 0 173 0'. = 0.01 level of signicance. 1 125 2 67 3 28 4 or more 7 State the appropriate null and alternative hypotheses. Choose the correct answer below. O A. H The population mean number of defective batteries is equal to O. 0 H A: The population mean number of defective batteries is greater than 0. B. Ho: The distribution of defective batteries is not binomial with n = 50 and p = 0.02. HA: The distribution of defective batteries is binomial with n = 50 and p = 0.02. O C. H0: The population mean number of defective batteries is equal to 0. H A: The population mean number of defective batteries is not equal 0. O D. H0: The distribution of defective batteries is binomiat with n = 50 and p =0.02. H A: The distribution of defective batteries is not binomial with n =50 and p = 0.02. The test statistic is x2 = -. (Round to three decimal places as needed.) The critical chi-square value is 1 (Round to four decimal places as needed.) Draw a conclusion. Choose the correct answer below. A. Do not reject the null hypothesis, and conclude that the retailer can evaluate this sampling plan using a binomial distribution with n = 50 and p = 0.02. O B. Reject the null hypothesis, and conclude that the mean number of defective batteries is greater than 0. O C. Do not reject the null hypothesis, and conclude that the mean number of defective batteries is 0. O D. Reject the null hypothesis, and conclude that the retailer cannot evaluate this sampling plan using a binomial distribution with n = 50 and p =0.02