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lowing queries will find the Name of the Employee and the name of the 2. Which of the following queries will find the Name Departments they work? 3. SELECT Dname, Ename FROM Dept d, EMP e, IN DEPT i: b. SELECT Dname, Ename FROM Dept d, EMP e, IN_DEPT i WHERE i.EID = e.EID AND d.DID = i.DID: c. SELECT Dname, Ename 5 CD FROM Dept d INNER JOIN IN DEPTI ON d.DID=i.DID INNER JOIN EMP e ON 1.EID = e.EID; d. SELECT Dname, Enane FROM Dept d NATURAL JOIN IN_DEPTI ON d.DID = i. DID NATURAL JOIN EMP e ON LEID = e.EID; e SELECT Dname, Ename FROM Dept NATURAL JOIN IN_DEPT NATURAL JOIN EMP; F. None of the above 3. Which of the following queries finds the number of employees: . SELECT count(*) FROM EMP; b. SELECT count(EID) FROM IN DEPT; L. SELECT count(DISTINCT EID) FROM IN DEPT; a SELECT DISTINCT count(ED) FROM IN DEPT; 2. SELECT count(*) FROM ( SELECT EID FROM IN_DEPT GROUP BY EID); ( None of the above ACE lowing queries will find the Name of the Employee and the name of the 2. Which of the following queries will find the Name Departments they work? 3. SELECT Dname, Ename FROM Dept d, EMP e, IN DEPT i: b. SELECT Dname, Ename FROM Dept d, EMP e, IN_DEPT i WHERE i.EID = e.EID AND d.DID = i.DID: c. SELECT Dname, Ename 5 CD FROM Dept d INNER JOIN IN DEPTI ON d.DID=i.DID INNER JOIN EMP e ON 1.EID = e.EID; d. SELECT Dname, Enane FROM Dept d NATURAL JOIN IN_DEPTI ON d.DID = i. DID NATURAL JOIN EMP e ON LEID = e.EID; e SELECT Dname, Ename FROM Dept NATURAL JOIN IN_DEPT NATURAL JOIN EMP; F. None of the above 3. Which of the following queries finds the number of employees: . SELECT count(*) FROM EMP; b. SELECT count(EID) FROM IN DEPT; L. SELECT count(DISTINCT EID) FROM IN DEPT; a SELECT DISTINCT count(ED) FROM IN DEPT; 2. SELECT count(*) FROM ( SELECT EID FROM IN_DEPT GROUP BY EID); ( None of the above ACE