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Please help show work Topic 5 Application: Conservation of Momentum and Energy Combination Answer the following questions, showing all work, including all units in all

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Topic 5 Application: Conservation of Momentum and Energy Combination Answer the following questions, showing all work, including all units in all calculations. Use only work and energy equations to solve the problems. Use the following equations to solve the problems: W = AKE + APE, + APE, mini + mzvzi = myvir + mzvzr (elastic collision) mivli + m2v2 = (mi + m2)vr (inelastic collision) A movie stunt man (mass 80.0kg) stands on a window ledge 5.0m above the floor (see drawing). Grabbing the rope attached to a chandelier, he swings down to grapple with the movie's villain (mass 70.0kg), who is standing directly under the chandelier. The stuntman releases the rope just as the touches the villain. . What is the velocity of the stunt man as he begins to collide with the movie's villain? (Conservation of energy) What is the velocity of the pair after they collide and begin to slide across the floor? (Conservation of momentum) If the coefficient of kinetic friction between their bodies and the floor is 0.250, how far do they slide? (Conservation of momentum) A 0.005kg bullet moving with an initial speed of 400m/s is fired into and passes through a 1.00kg block of wood. The block, initially at rest on a frictionless, horizontal surface, is connected to a spring with a spring constant of 900N/m. The block moves 0.050m to the right immediately after impact. . Find the velocity of the block just after the collision. (Conservation of energy) Use the velocity of the block after the collision to find the speed the bullet as it emerges from the block. (Conservation of momentum) A 0.025kg bullet traveling 230m/s buries itself in a 3.6kg pendulum hanging on a 2.8m string, which makes the pendulum swing up in an arc. . Find the velocity of the bullet/block system just after the collision. Determine the final height of the pendulum . A block, M1=10kg, slides down a smooth, frictionless incline of height 5m. It collides elastically with another block, M2=5kg, which is sitting at the bottom of the incline. Assume the first block comes to rest after the collision. The second box travels over a rough surface (HK = 0.5) for 2m. At the end of the rough surface there is a spring of spring constant 250N/m. The spring is on a frictionless surface What is the velocity of the first block as it approaches the second block at the bottom of the incline? (Conservation of energy What is the final velocity of the second block after the collision? Conservation of momentum) What is the velocity of the second block after the slide across the floor and just before it touches the spring? (Conservation of energy) By how much would the second block compress the spring? (Conservation of energy)

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