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5. Suppose that XI: := (11, ..., In) is a sample from {fo : 0 6 0} and that we have a prior T(0) on 0. If we also have an additional sample Xn+lintm := (In+1,..., In+m), show that using the posterior #(0 | X1:n) as a prior and then conditioning on X,+1in+m is the same as the posterior obtained by using the prior #(0) and conditioning on X1antm = ($1, . . ., In, In+1, . .., Intm)