Please replicate the expected output 1 for 1 with no differences. Thanks

Complete the following code to count the number of occurences of distinct words in the result of Question 4 The expected output is [['writing', 1], ['programs', 2], ['is', 1], ['a', 3], ['very', 1], ['creative', 1], ['and', 2], ['rewarding', 1], ['activity', 1], ['says', 1], ['university', 1], ['of', 1], ['michigan', 1], ['coursera', 1], ['instructor', 1], ['charles', 1], ['r', 1], ['severance', 1], ['in', 1], ['his', 1], ['book', 1], ['python', 1], ['for', 2], ['everybody', 1], ['you', 1], ['can', 1], ['write', 1], ['many', 1], ['reasons', 1], ['ranging', 1], ['from', 1], ['making', 1], ['your', 1], ['living', 1], ['to', 3], ['solving', 1], ['difficult', 1], ['data', 1], ['analysis', 1], ['problem', 2], ['having', 1], ['fun', 1], ['helping', 1], ['someone ', 1], ['else', 1], ['solve ', 1] ] Tips: Use dir( ) and help( ) to find which list method can give us the number of occurences of a specific element output = ['writing', 'programs', 'is', 'a', 'very', 'creative', 'and', 'rewarding', 'activity', 'says', 'university', 'of', 'michigan', 'and', 'coursera', 'instructor', 'charles', 'r', 'severance', 'in', 'his', 'book', 'python', 'for', 'everybody', 'you', 'can', 'write', 'programs', 'for', 'many', 'reasons', 'ranging', 'from', 'making', 'your', 'living', 'to', 'solving', 'a', 'difficult', 'data', 'analysis', 'problem', 'to', 'having', 'fun', 'to', 'helping'. 'someone', 'else', 'solve', 'a', 'problem'] word_list =[ ] word_count_list = [ ] for word in output: \# if \# word_count_list. append(__) \# word_list.append(__) print(word_count_list)