PLEASE USE OCTAVE OR MATHLAB CODING AND EXPLAIN IN DETAIL. THANK YOU

To prevent shrinkage when a pivot is fitted into a steel hub, the pivot has to be cooled based to the equation below: f(T) = -0.50598x10-107; +0.38292x10-?;* +0.74363x10-*T, +0.88318x10-2 = 0 1.1. Use the Bisection method to find T;; with the initial and final temperature Tri = -150C and Tys = -100C, respectively, and a tolerance of 1e-10 1.2. Use the secant method to find Tr: with the initial and final temperature Tja = - 150C and T, = -100C, respectively, and a tolerance of 1e-10