Pr 1. Below, I show a computation of the derivative for f(x). Label each arrow, - , with a brief name of the rule used for that operation. For instance, (5x)' - 5(x)' might be labeled "taking constant out". Don't worry about using "official" Rule names. f ( x) = (3 x2 - 8 x+ 1 X (3 x2 - 8 (3 x2 - (8) ' - (3 x2) 1 + 3. (x2) " + 3 . 2X =6x 1 X + ( X ) + -+ 1 - X X x2 f' (x) = (3x2 - 8 x+ $ 3 x2 - 8) ' X + - + 3 x2 - 8) X + = X X X 1 + 3 x2 - 8) 1 - 1 6 X X + - = we'll leave it like this x2