Problem 2. A thin-walled tube, as in Figure below, is loaded with an internal pressure p and has a longitudinal through-wall crack of length 2a. Stress intensity factors for this case from Tada (2000) are K = F(pravg/t), where FF(), =a/Tavgt F= 1+1.2522 for 1, and F0.6+0.92 for 1x5 2a crack Tavg pressure The material is titanium 6Al-4V alloy (annealed), the pressure is p = 40MPa, and the tube dimensions are lavg = 50 and t = 4 mm. A crack of tip-to-tip length 2a = 20mm may be present. What is the safety factor against fracture? What is the safety factor against yielding with no crack present? Is the tube safe to use if failure could present a safety hazard? a P Or a 61 60 d 64 60 L e: Hoop stress :Longitudinal stress , :Radial stress L: Cylinder length d: Cylinder diameter t: Cylinder Thickness P: Internal presser