Problem 6. Heating Curve for Water The Hrap of water is 40.7kJ/mol. The enthalpy of fusion (AH/ma) of H2O is 6.01kJ/mol. The specific heat of liquid water is a constant equal to 4.18J/(g+C); for ice, the specific heat is 2.06J/gC; for steam's specific heat is 2.02J/g1C. Calculate how many Joules of energy would be required to change 150.0g of water at 20.0,9C to steam at 120C. You will need to break this problem into four steps. a) Find the heat needed to warm up the ice to the melting point (one phase only). b) Find the heat for the transition of ice into liquid water (two phases). c) Find the heat needed to warm up the liquid water to the boiling point (one phase only). d) Find the heat needed to vaporize the liquid water into steam (two phases). e) Find the heat needed to heat the vapor (steam) from the boiling point to 120C (one phase only). f) Add all the heats calculated above in steps a,b,c,d, and e. Watch the units