Problem 7 (10 points) Translate the following loop into C. Assume that the C-level integer j is held in register St, and Ss2 holds the C-level integer called result, and Ss0 holds the base address of the integer array MemArray addi $tl, $0, $0 lw $s1, 0 (s0) add s2, $s2, $s1 addi $s0, $s0, 4 addi $t1, $tl, 1 slti $t2, $t1, 400 bne $t2, $0, LOOP LOOP