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procedure divide ( n: positive integer ) while n > 0 m : = ( 2 n + 5 ) / 4 n : =

procedure divide(n: positive integer)
while n >0
m :=(2n +5)/4
n := n 1
return m
What is the best-case scenario time complexity of this algorithm?
Group of answer choices
\Omega (n)
\Omega (n2)
\Omega (1)
\Omega (logn)

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