Answered step by step
Verified Expert Solution
Link Copied!

Question

1 Approved Answer

Procedure Set 1 (near) 1. Find any two grocery items which are factory produced stored near each other from the kitchen cabinets, refrigerators or dining

image text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribedimage text in transcribed
Procedure Set 1 (near) 1. Find any two grocery items which are factory produced stored near each other from the kitchen cabinets, refrigerators or dining table. 2. Measure the distance between the two items in meters using a ruler or measuring tape. 3. Write down the weight in kilograms printed at the back of the item. Convert if necessary. 4. Ask someone to take your photograph while accomplishing performance task. 5. Solve the Gravitational Force. What is asked? What is the gravitational force, between two items, with their centers separated by the distance measured? What is/are given? M1 = kg; M2 = kg; D = m Universal Gravitational Constant is G = 6.67 x 10-1iNm2/kg2 Solution solving for unknown (6.67 x 10-11 Nm2/kg2) (_kg)(_ kg) Fq = _Gmjm2 Fa = m ) 2 Answer Fg = N Procedure Set 2 (far) 6. Find any two grocery items which are factory produced stored far from each other from the kitchen cabinets, refrigerators or dining table. 7. Measure the distance between the two items in meters using a ruler or measuring tape. 8. Write down the weight in kilograms printed at the back of the item. Convert if necessary. 9. Ask someone to take your photograph while accomplishing performance task. 10. Solve the Gravitational Force. What is asked? What is the gravitational force, between two items, with their centers separated by the distance measured? What is/are given? M1 = kg; M2 = kg; D = m Universal Gravitational Constant is G = 6.67 x 10-13Nm2/kg2 Solution solving for unknown (6.67 x 10-1 Nm2/kg2) ( kg)(_ kg) Fa = Gmim2 Fg = m ) 2 Answer Fq = N Generalization/Conclusion: What does the difference in distance imply?Procedure 1. Ask someone to take your photograph while accomplishing performance task. 2. Cut 3 pieces of strings same as your height, as long your arm, and as wide as your palm, then attach a piece of weight for your bob. 3. Find a place outside the house where you can hang the 3 strings with bobs (weights). 4. Measure and record the length of the string using a ruler (or measuring tape). 5. Prepare to record time for 10 complete swings each string set. 6. Pull the bob to one side and let it swing for 10 times, one after another string. 7. Calculate the frequency and its period for each string that completes 10 cycles in each individual times. Table: (18 pts) String 1 (length same as String 2 (length of arm) String 3 (width of palm) person's height) Time recorded for 10 time = time = time = swings Frequency cycles cycles cycles f = f = f = time time time Period 1 1 1 T = 7 T = = T= = = Generalization/ Conclusion: What does the difference in frequency suggest?A mass of 0.25 kg is placed on a vertical spring and the spring stretches by 10 cm. It is then pulled down an additional 6 cm and then released. a. Find the spring constant k b. The angular frequency w c. The frequency f d. The period T e. The maximum velocity of the vibrating mass f. The maximum acceleration of the mass g. The maximum restoring force h. The velocity of the mass at x = 3.0 cm m = 0.25 kg; l = 10 cm; a. solving for spring constant using Hooke's law FA mg k = X X mg k = = Xb. angular frequency a = c. solving for frequency of the motion W f=: 2n rad d. solving for Period of the motion 1 T =-: e. solving for maximum velocity Vmax = WA f. solving for maximum acceleration amax = WA g. solving for maximum restoring Force from Hooke's law F = kx Fmax = kxmax h. solving for the velocity of mass at x = 3 cm v = +WVA2 - x2What is asked? Calculate the frequency and its period of a child's swing that completes 20 cycles in 25 s. What is/are given? cycles = 20; time = 25 s Solution solving for unknown cycles f = Frequency (f) = cycles time time time T = Period (T) = T = cycles Answer What is asked? Determine the frequency and the period of a metronome that clicks 80 times in 20 s. What is/are given? cycles = 80; time = 20 s Solution solving for unknown cycles Frequency (f) = cycles f = time time time T = Period (T) = T= cycles AnswerFind the period of a simple pendulum 1.25 m lon . l = 1.250 m solving for unknown l T =er : F Jr; Find the length of a pendulum whose 'od is 2.00 5. T = 2 no 5 solving for unknown T1\"2 1 = m9 = A pendulum 1.25 m lung is observed to have a period of 2.244 s at a certain location. Find the acceleration of gravity mere. T : 2.244 3; l: 1.25m solving for unknown 41:2 To A periodic transverse wave is created by shaking one end of a string side to side periodically. Sixty oscillations are completed in 10.0 seconds. It is observed that the waveform repeats every 0.5 m. Determine/ Calculate the following: a. Wavelength of the wave b. Frequency of the wave c. Period of the wave d. Speed of the wave 1 = 0.5 m; t = 10.0 s; cycles = 60 solving for unknown a. b. cycles f = time C. T d. v = if or v = =1. A periodic transverse wave is created by shaking one end of a string side to side periodically. Ten oscillations are completed in 2.0 seconds. It is known that the wave speed is 2.0 m/s. Calculate a. the frequency of the wave, cycles f : time b. period of the wave, T =- f c. and the wavelength. 1 = VT 2. A periodic transverse wave is created by shaking one end of a string side to side periodically. It is observed that the wave length is 0.100 m, and the speed of the wave is 2.00 m/s. Calculate a. the frequency and v = af b. period of the wave. T= = = 3. The human ear can hear sounds from a low of 20 Hz up to a maximum of about 20,000 Hz. If the speed of sound in air at a temperature of OC is 331-, find the wavelength and the period associated with these frequencies. 20 Hz V T = = = 20,000 Hz V 1 = T = 4. A sound wave has a wavelength of 2.25 x 10-2 m and a frequency of 15,000 Hz. Find its speed. v = af 5. Find the wavelength of a sound wave of 60.0 Hz at 20.0 C. v = (331 + 0.606t)

Step by Step Solution

There are 3 Steps involved in it

Step: 1

blur-text-image

Get Instant Access to Expert-Tailored Solutions

See step-by-step solutions with expert insights and AI powered tools for academic success

Step: 2

blur-text-image

Step: 3

blur-text-image

Ace Your Homework with AI

Get the answers you need in no time with our AI-driven, step-by-step assistance

Get Started

Recommended Textbook for

Physics

Authors: John D. Cutnell, Kenneth W. Johnson

9th edition

470879564, 1118424840, 470879521, 9780470879566, 9781118424841, 978-0470879528

More Books

Students also viewed these Physics questions

Question

Why is understanding accounting important to nonaccountants?

Answered: 1 week ago