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Python code which runs in less than 1 0 seconds for : There are 4 arrays of data. The arrays cat [ n ] and

Python code which runs in less than 10 seconds for :
There are 4 arrays of data. The arrays cat[n] and cnt[n] are each of n integers, and cat[i] relates to cnt[i]. These represent a category and count at each index.
There are also two arrays of integers that represent q queries. The arrays l[q] and r[q] contain 1-based indices for the left and right ends of subarrays to consider in cat and cnt.
Process the queries in order. Create an array of q values where answer i relates to query i.
For each query i:
Within the subarrays in cat and cnt, determine the maximum cnt for each cat.
Store the sum of these maxima as the answer to the query.
Clear the cnt values in the range.
After all queries are processed, return the answer array.
Example:
n=5
q=2
cat =[1,2,1,1,3]
cnt =[5,3,4,5,2]
l =[1,1]
r=[3,5]
First query [1,3]:
Category 1 has two occurrences, with a maximum count of 5. Category 2 occurs once with a count of 3.
The answer to the first query is 5+3=8. Delete the values within the range and
go to the next query.
Second query [1,5]:
Categories 1 and 3 each occur once with counts of 5 and 2. The answer to the
second query is 5+2=7. Delete the values within the range.
There are no more queries, so return the answer array [8,7]
Function Description
Complete the function segmentMax in the editor below.
segmentMax has the following parameters:
int cat[n]: categories
int cnt[n]: counts
int l[q]: left indices of queries (1-based)
int r[q]: right indices of queries (1-based)
Return
int[q]: the sums of maxima by type for each query range
Constraints
1<= n, q<=100000
1<= cat[i]<=10000
1<= cnt[i]<=100000
1<= l[i]<= r[i]<= n

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