Q1 (0.75 points) Figure below shows an arrangement of four charged particles with 6230.00 and the distance d = 2.00 cm. Particle 2 19 C. has charge q2 = + 800 X 1019 C; particle 3 and 4 have charges q3 = q4 = 1.60 X 10 (a) What is distance D between the origin and particle 2 if the net electrostatic force on particle 1 due to the other particle is zero? (b) If particles 3 and 4 were moved closer to the x axis but maintained their symmetry about that axis, would the required value of D be greater than, less than, or same as part (a)? Q2 (0.75 points) Figure below shows a plastic ring of radius R = 50.0 cm. Two small charged beads are on the ring: Bead 'l of charge +2.00 uC is fixed in place at the left side; bead 2 of charge +6.00 uC can be moved along the ring. The two beads produce a net electric field of magnitude E at the center of the ring. At what: (a) Positive and (b) Negative value of angle 0 should bead 2 be positioned such that E = 2.00 X 105 N/C? Q3 (0.75 points) In figure below, an electron is shot at an initial speed of v0 = 2.00 X 106 m/s at angle 60 = 40.00 from an X axis. The electron moves through a uniform electric field E = (5.00 N/C) j. A screen for detecting electrons is positioned parallel to y axis, at distance x = 3.00 m. In unit-vector notation, what is the velocity of the electron when it hits the screen? Detecting Screen Q4 (0.75 points) A thin, uniformly charged rod of length L, carrying total charge Q, lies on the x axis between x=0 and x=L. Starting from E = fke% r, derive an expression for the electric field at the point (3L, 0) on the x axis. Use x as the integration variable, and include the following steps: (a) draw the charge element dq, the vector r and the field element dE (produced by dq) on the diagram; (b) express the integrand in terms of x, and do the integral; (c) simplify the expression, writing the answer in terms of Q and L