Qa Given the code snippet below, what would be the output after the code executes? public class Person ( } public void display() { } public class Student extends Person { public void display() { } O a. Q System.out.println("Person"); public static void main(String[] args) { Student student = new Student (); Person person = student; } System.out.println("Student"); O b. Student Student person.display(); student.display(); O c. Person Person Person Student O d. Student Person } Given the code snippet below, what would be the output after the code executes? public class Person { public void display() { System.out.println("Person"); public class Lecturer extends Person { public void myMethod () { System.out.println("Method in Lecturer"); } public static void main(String[] args) { Person objRef= new Lecturer(); objRef.display(); objRef.myMethod(); O a. The code will not execute as there is a compile-time error. O b. Person Method in Lecturer O c. Method in Lecturer Person (3 O d. The code will not execute as there is a run-time error. Which is NOT a correct explanation of the code given below. public class Person { public String name; public void display() { } } System.out.println("Person"); public class Lecturer extends Person ( public int age; public void display() { } System.out.println("Lecturer"); } public static void main(String[] args) { Person objRef = new Lecturer(); objRef.name= "Goo"; Lecturer lec (Lecturer) objRef; lec.age = 21; objRef.display (); lec.display(); System.out.println(lec.name "/" lec.age); O a. Person objRef = new Lecturer(); objRef.name = "Goo"; is an example of Upcasting O b. Lecturer lec = (Lecturer) objRef; lec.age = 21; O c. objRef.display(); lec.display(); outputs: Lecturer Lecturer O d. System.out.println(lec.name + "/" + lec.age); outputs: Goo/21 Oe. The code will not compile.