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Question 1 4 pts / * Find the first element in A that is not also in B . A , int * B ,

Question 1
4 pts
/*
Find the first element in A that is
not also in B.
A, int*B, int nA, int nB)
{
int pos =;
while (pos nA & & find (B,B+nB,A[pos])B+nB)
{
}
++pos;
if (pos >= nA)
{
pos =-1;
}
}
return pos;
}
According to the copy-and-paste technique, how would you annotate line 4 of this function by the time you had determined the complexity of the entire loop?
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