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Question 1 L(A) 2.0 cm 1.0 cm (s) 0.01 0.02 A 2.00 cm diameter, 6.00 cm long solenoid has 116 turns and has a
Question 1 L(A) 2.0 cm 1.0 cm (s) 0.01 0.02 A 2.00 cm diameter, 6.00 cm long solenoid has 116 turns and has a 1.00 cm diameter loop inside it. The loop has a resistance of 0.400 Q. What is the current in the loop at 0.0130 s? The the maximum and the minimum current in the graph have the same magnitude which is 0.700 A. Question 2 An LC circuit is built with an inductor L = 7.50 mH and a capacitor C = 71.1 pF. If the capacitor voltage has its maximum value of V = 2.91 V at t = 0 s, what is the inductor current if the capacitor is fully discharged? Answer: 8. (Knight Problem 30.41) A 10 cm x 10 cm square loop lies in the xy-plane. The magnetic field in this region of space is B = (0.30ti + 0.50) T, where t is in s. What is the emf induced in the loop at (a) t = 0.5 s and (b) t = 1.0 s? [Answer: a. 5.0 mV. b. 10.0 mV.] 9. (Knight Problem 30.46) FIGURE P30.46 shows a 4.0-cm- diameter loop with resistance 0.10 around a 2.0-cm- diameter solenoid. The solenoid is 10 cm long, has 100 turns, and carries the current shown in the graph. A positive cur- rent is cw when seen from the left. Find the current in the loop at (a) t=0.5 s, (b) t = 1.5 s, and (c) t = 2.5 s. [Answer: a. 0.0 A. b. 0.16 mA. c. 0.0 A.] Isol (A) 20 4.0 cm 2.0 cm 0 t(s) 3 -20- FIGURE P30.46 10. (Knight Problem 30.53) The square loop shown in FIGURE P30.53 moves into a 0.80 T magnetic field at a constant speed of 10 m/s. The loop has a resistance of 0.10 2, and it enters the field at t = 0 s. a. Find the induced current in the loop as a function of time. Give your answer as a graph of I versus t from t = 0 s to t = 0.020 s. b. What is the maximum current? What is the position. of the loop when the current is maximum? [Answer: 11 A, halfway.] 10 cm 10 cm FIGURE P30.53 10 m/s XEX x xx B=0.80 T X X XX X X
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