Question 2 (1 point) What is the MAC address used for a broadcast by Ethernet? Question 3 (1 point) The first 3 bytes of an Ethernet MAC address identify the manufacturer of the NIC. What is the abbreviation (in upper case) that is used for identifier? A Question 4 (1 point) What protocol is used on an Ethernet LAN by a host that wants to know (learn) the MAC address of another host on the network? You can assume this is an IP network. O DNS O UDP O ARP Question 5 (2 points) Time Source Denton Protocol Length Indo 1 0.000000 EdimaxTe_02:0a: 6a Broadcast ARP 42 who has 172.16.255.2547 Tel1 172.16.254.2 2 0.001010 Cisco le:eb: 60 EdimaxTe_02:0a: 6a ARP 60 172.16.255.254 is at 00:00:30:le:eb: 60 Frame1: 42 tytes on wire 330 Id2 bytes captured 330 bits) B Ethernet II. Sre: EdimaxTC_02: 06 (00:0e: 20:02:0a76a), Dst: Broadcast fffff:ffff:ff) Destination: Broadcast (ff:ff:ff:ff:ff:ff) Source: EdimaxTe_02:0a:6a (00:0e: 2:02:0a: 6a) Type: ARP (0x0806) Address Resolution Protocol (request) Hardware type: Ethernet (1) Protocol type: IP COX0800) Hardware size: 6 Protocol size: 4 Opcode: request (1) [is gratuitous: False) Sender MAC address: Edimaxe_02:0a:62 (00:0e: 2:02:0a: 6a) Sender IP address: 172.16.254.2 (172.16.254.2) Target MAC address: 00:00:00 00:00:00 00:00:00:00:00:00) Target IP address: 172.16.255.254 (172.16.255.254) A good reference for ARP is https://en.wikipedia.org/wiki/Address_Resolution Protocol Based on frame 1 which of the following statements are true (3 correct choices) The host with the IP address 172.16.255.254 is trying to find the MAC address of the host with IP address 172.16.254.2 The host requesting the MAC address sends it's request as a unicast message The MAC Address for the host with the IP address 172.16.254.2 is 00:0e:20:02:0a:6a The MAC address for the host with the IP address 172.16.255.254 is 00:0e:2:02:0a:6a The host with the IP address 172.16.254.2 is trying to find the MAC address of the host with IP address 172.16.255.254 The host requesting the MAC address sends it's request as a broadcast Question 6 (2 points) 10.000000 EdimaxTe_02:0a: 6a Broadcast ARP 42 who has 172.16.255.254? Tell 172.16.254.2 20.001010 Cisco le:eb: 60 Edimaxte 02:0a: 6a ARP 60 172.16.255.254 15 at 00:00:30:le:eb: 60 Frame 2: 60 bytes on wire (480 bits). 60 bytes captured (480 bits) Ethernet II, Sre: cisco le:eb: 60 C00:0c:30:1e:eb:60). Ost: EdimaxTe 02:0a: ba (00:0e: 2e:02:0a: 6a) Destination: EdimaxTe_02:0a: 6a (00:0e: 2e:02:0a: 6a) Source: Cisco le:cb:60 (00:0c: 30:le:eb:60) Type: ARP (0X080G) Trailer: 000000000000000000000000000000000000 Address Resolution Protocol Creply) Hardware type: Ethernet (1) Protocol type: IP (0X0800) Hardware size: 6 Protocol size: 4 Opcode: reply (2) [Is gratuitous: False] Sender MAC address: Cisco_le:eb: 60 (00:0c: 30:le:eb: 60) Sender IP address: 172.16.255.254 (172.16.255.254) Target NAC address: Edimaxle_02:0a: 6a (00:0e: 2e:02:0a: 6a) Target IP address: 172.16.254.2 (172.16.254.2) Based on frame 2 which of the following statements are true The MAC address for the host with the IP address 172.16.255.254 is 00:00:30:1e:eb:60 The host sending this packet has the IP 172.16.255.254 The host with the IP address 172.16.255.254 is trying to find the MAC address of the host with IP address 172.16.254.2 This a broadcast Ethernet frame The Mac Address for the host with the IP address 172.16.254.2 is 00:00:30:1e:eb:60 This is a unicast frame Question 7 (1 point) Referring to step 3c of task 3, why did your laptop ARP for the MAC address of your default gateway when you were trying to reach the college web server? O All local and remote communications are sent to the router! The web server is on a different network segment, therefore all remote communications are directed to my router's MAC address. My laptop needs to obtain the web server's MAC address and since it is on a remote network, it sends the ARP request to my router who knows the remote and local MAC addresses. None of the answers! Question 8 (1 point) If an Ethernet frame is carrying an IP packet what would the type/length field value be? include the leading Ox in your answer Hint: Examine the HTTPS request/response in your Task 3 Wireshark capture. A/ Question 9 (1 point) Let's assume for a moment that your partner has connected her/his laptop to the same network as you. Furthermore, let's assume the following: Your IP address: 192.168.20.143 255.255.255.0 Your partner's IP address: 192.168.20.150 255.255.255.0 What would the ARP request look like if your were to attempt to video conference with your partner? Read the blurb on ARP Resolution Protocol if you can't remember what ARP is. The arp request will look something like: Who has 192.168.20.1? Tell 192.168.20.143 Source MAC: Your laptop's MAC address Destination MAC: broadcast Note: 192.168.20.1 is your default gateway's ip address. Local or remote communication is performed via the gateway! OMAC addresses are not needed for location communications. ARP is not used for local communications! The arp request will look something like: Who has 192.168.20.150? Tell 192.168.20.143 Source MAC: Your laptop's MAC address Destinatino MAC: broadcast