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Question 2 Not yet answered Marked out of 1.50 Flag question The following function takes a single-linked list of integers as a parameter and rearranges the elements of the list. The function is called with the list containing the integers [10, 4, 12, 14, 1, 8, 3] in the given order. What will be the contents of the list after the function completes execution? void rearrange (Node list) { Node p, q; int temp; if (list == null || list.next == null) { return; } P = list; q = list.next; while (q != null) { temp = (int) p.element; p.element q.element; q.element P = q.next; I temp; p = null ? p.next : null; OA. [4, 10, 12, 14, 8, 1, 3] OB. [10, 4, 12, 14, 1, 8, 3] O C. [4, 10, 14, 12, 8, 1, 3] OD. [1, 14, 12, 4, 10, 8, 3]