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Question 9 The table below contains the birth weights in grams of 26 African American babies born at BayState Medical Center in Springfield, Massachusetts in

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Question 9 The table below contains the birth weights in grams of 26 African American babies born at BayState Medical Center in Springfield, Massachusetts in 1986. Compute a 95 confidence interval for birth weight. Directions: Click on the Data button below to display the data. Copy the data into a statistical software package and click the Data button a second time to hide it. Data Weight 2497 2763 2879 2887 2940 2973 2973 3072 3033 1323 3:367 3416 3409 3815 3823 1143 1715 1944 2133 2146 2309 2351 2416 2408 2414 24713072 3033 1323 8367 3416 3409 3819 3823 1143 1715 1944 2133 2146 2309 2351 2416 2408 2414 2471 1. Find the point estimate for the birth weights. Round your answer to 2 decimal places. 2. Determine the value of te- Round your answer to 5 decimal places. 3. Find the margin of error for the confidence interval. Round your answer to 1 decimal place. 4. Construct the confidence interval for birth weights. Enter your answer as an open interval of the form (a,b) and round to the nearest integer. 5. Babies weighing less than 2500 grams are considered to be of low birth weight. Can you conclude that the average birth weight is greater than 2500 grams? O Yes, the entire confidence is above 2500. O No conclusions can be drawn since the confidence interval contains 2500. O No, the entire confidence interval is below 2500.Question 5 7.2/8 pts 0 1-2 Score on last try: 7.2 of 8 pts. See Details for more. > Next question Get a similar question You can retry this question below On a peer-to-peer (P2P) lending website, borrowers complete an approval scoring form that lenders use to assess creditworthiness. Borrowers are rated A, B, C or D, based on their scores, with A having the highest scores and D having the lowest. In a large sample of borrowers, 14% were rated A, 28% were rated B, 33% were rated C, and the rest were rated D. Suppose the scores are normally distributed with a mean of 321 and a standard deviation of 50. Round numeric answers to the nearest integer. a) What is the cut-off score between A and B? |375.025 b) What is the cut-off score between B and C?| 331.094v c) What is the cut-off score between C and D? | 287.275 d) What score corresponds to the 65th percentile? 340.266 e) What score corresponds to the 10th percentile? | 256.922 f) What is the minimum score above which lies 8% of the scores?. Question 1 0/1 pt 0 3 0 A hypothesis test was conducted to investigate whether the population mean age of college students at Osler city is less than 23. a) This is a O left-tailed test. O right-tailed test. O two-tailed test. O half-way test. b) Select a correct formulation of the appropriate hypotheses: O Ho: u 23 O Ho: H = 23 HI:u > 23 Hip 23 O HO: H 23 HI:u = 23 Check Answer. Question 3 Testing: Ho: / 2 24.3 H1:p 2.33 Oz 2.05 Oz 2.33 Oz > 2.05 c) The decision is to O Reject the null hypothesis O Accept the null hypothesis O Accept the alternative hypotheis OFail to reject the null hypothesis d) Suppose you mistakenly failed to reject the null hypothesis in this problem, what type of error is that? O Type II O Type I. Question 4 You are conducting a study to test a claim that the mean income of regular casino visitors is significantly less than $100,000. A random sample of 56 regular casino visitors had a mean income of $95,483. Do the sample data provide convincing evidence to support the claim? Assume o is known to be $24,000. Conduct a hypothesis test using a 1% level of significance. Give numeric answers to at least 2 decimal places. What are the correct hypotheses? (Select the correct symbols and values.) Ho: Select an answer ? H1: Select an answer V ? Based on the hypotheses, find the following: Test Statistic = Critical-value = The correct decision is to | Select an answer The correct conclusion would be: Select an answer that the mean income of regular casino visitors is significantly less than $100,000Question 7 Score on last try: 3.64 of 4 pts. See Details for more. > Next question You can retry this question below The manufacturer of a particular brand of tires claims they average at least 85,000 km before needing to be replaced. From past studies of this tire, it is known that the population standard deviation is 12,700 km. A survey of tire owners was conducted to determine if the mileage of the tires is lower than 85,000 km. From the 42 tires sampled, the mean lifespan was 79,500 km. Testing at o = 2%, can we prove that the data is inconsistent with the manufacturers claim? A. We should use a z v test. B. What are the correct hypotheses? Ho: M 85000 H1:M V 85000 Based on the hypotheses, find the following (round correct to at least 2 decimal places): C. Test Statistic = -2.81 D. Critical Value = -2.518 x (note the direction of H1)Question 8 Score on last try: 2.25 of 3 pts. See Details for more. > Next question You can retry this question below In conducting the hypothesis test below, your sample consists of 22 observations, with a mean of 28.2 and standard deviation of 1. Ho: u = 28.6 H1:u # 28.6 a) This is a two-tailed test. V b) Calculate the test statistic, rounded to 3 decimal places. t= -1.83:X

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