Question 9.14 a) We know that the area between 0 and z is 0.1480. We can find Z value by looking at the table and finding the row and column that correspond to the value 0.1480. Solution: Z value is 0.38. b) We know that the probability of the area to the right of z is 0.7324. Since the area is greater than 0.5, we know that z must lie to the left of 0 and is negative. Therefore we can find the area between O and z by subtracting 0.5 from 0.7324, which is 0.2324. We can find it by looking at the table and finding the row and column that correspond to the value 0.2324. Solution: Z value is -0.62. 3 c) We know that the probability of the area between -z and z is 0.9328. We know the area between O and z is the same as the area between 0 and -z, which is the same by symmetry. We can find the area between 0 and z by dividing 0.9328 by 2, which is 0.4664. We can find it by looking at the table and finding the row and column that correspond to the value 0.4664. Solution: Z value is 1.83. 9.14 Find z if the standard-normal-curve area (a) between 0 and z is 0.1480; (b) to the right of z is 0.7324; (c) between-z and z is 0.9328.