Question: Combinational Logic Design. The logic symbol of the combinational circuit is given below. A. 1, Priority Encoder X Code Converter (X+4)%3 2 to 4 Demultiple xer 12 A. B. B Provide three separate Truth Tables for Priority Encoder, Code Converter and De-Multiplexer. Make sure you correctly write inputs and outputs in each truth table and in correct order (such as highest priority bit on the left side). In Karnaugh Maps, show the GROUPINGS on the K-Maps. The priority encoder The priority encoder takes four bits input I (1, 1, 1, 1) and produce a two bit code X (XX.). The working principle of the priority encoder is as follows: X X 1.-1 1 1-1 1s=1 1 1,-1 0 1 0 0 0 1 Using a truth table and Karnaugh maps, find the simplified Boolean Expressions of X, and X. The code converter The working principle of the code converter is as follows: It takes the input X, X, and applies (X+4y%3 to produce two bits output K, and K. In particular, it adds 4 to X, and then applies mod 3 (that is remainder after division to 3). Eg. 5+4-9%3-0 Using a truth table and Karnaugh maps, find the simplified Boolean Expressions of K, and K. The De-Multiplexer The De-multiplexer takes S, K, and K, as inputs and produces 4 outputs A1, A, B and B. The working principle of the de-multiplexer is as follows: IfS - 1, then select the output channel B If S = 0, then select the output channel A Using a truth table and Karnaugh maps, find the simplified Boolean Expressions of A, A, B, and B. Finally, draw the logic circuit from inputs 1; 1; 1, 1. to A, A., B, and B, using the Boolean Expressions you found in the previous step. Then test, I=1101 and S=1 on the circuit. What are the values of A1, A, B and B