question is: consider the above ICMP echo request message captured by wireshark and answer the following questions

PLEASE BE QUCK

No Time Source Destination Protocol Length into 241 43.644153 192.168.1.102 128.59 23.100 CM teha ping request Frame 241:582 bytes on wire (4656 bits). 582 bytes captured (4656 bits) Ethernet It Sre: Actionte_8a:70:1 (00:20:e0:8a:70:1a). Ost: LinksysG_daat:73 (00:06:25.da:af:73) Internet Protocol Version 4. Sre: 192.168.1.102. Dst: 128.59.23.100 0100 .... Version: 4 0101 = Header Length: 20 bytes (5) Differentiated Services Field: 0x00 (DSCP: CSO, ECN: Not-ECT) Total Length: 568 Identification: 0x332a (13098) Flags: Ox01 0... .... = Reserved bit: Not set ........ = Don't fragment: Not set ..0. .... = More fragments: Not set Fragment Offset: 2960 Time to Live: 8 Protocol: ICMP (1) Header Checksum: 0x227c (validation disabled] [Header checksum status: Unverified] Source Address: 192.168.1.102 Destination Address: 128.59.23.100 [3 IPv4 Fragments (3508 bytes): #239(1480), #240(1480), #241(548)] Internet Control Message Protocol a (40) How can you create an ICMP echo request message? b. (4p) How many bytes are there in the IP header of this datagram? How many bytes are there in the payload of the IP datagram? Explain how you determined the number of bytes in the payload c. (Ap) What information in the IP header indicates that this IP datagram has been fragmented? d. (p) Is this fragment the first, second or last fragment? How can you tell? e. (4p) What was the size of the IP datagram before fragmentation