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Rate Law from Initial Rates (B) 2010 2009 100 free vom DO 0.050.64 Dis 10 13:10 which there to the area with the experts that

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Rate Law from Initial Rates (B) 2010 2009 100 free vom DO 0.050.64 Dis 10 13:10 which there to the area with the experts that the recomana e ferro chimbe che O, OH OH-400, Oooooo 00VNO 100 LOKO.COM thes for at start 3 strul cospermetre (colo - 0.210 mat troi, -0.00 mott? Rate Law from Initial Rates (B) 200%*) +20+0000; The above reaction was studied at a partiter temperature) and the following data (for rate 400V) were obtained tool for the mot (m) 0.090 0.050 0.180 0.025 1,931 0.180 0.050 3610 Which of the following expressions for the ratelow are consistent with the above experimental data Note that the rate constant may be different for each of the choices below (lekin choice A may be not equal to in chien [CIO, 10 000 KOH0012 - 00101/ -2010/01 - 100 [10]/et - KOH0031 warcio'dt K(COO) ipts Tries 0/5 For Rated[CIO, I/dt, calculate the rate constant (K). (Units required Ipts ER Thies 0/5 What would be the initial rate (-dicial/t) for an experiment with (Colo 0.210 molland [Oklo 0.0446 mol/l (Units required) 22 Tries 0/5 Rate Law from Initial Rates (B) - 2C102(aq) + 2OH(aq) + C103"(aq) + C102 (aq) + H2O(1) The above reaction was studied (at a particular temperature) and the following data (for rate --d[C1021/ct) were obtained: [CO2lo [OH ). Initial Rate (moll) (mol/L) (mol Ls) 0.090 0.050 9.64 x 10-2 0.180 0.025 1.93101 0.180 0.050 3.86x10-1 Which of the following expressions for the rate law are consistent with the above experimental data. Note that the rate constant may be different for each of the choices below (l.e. k in cholce A may be not equal to k in choice B etc). Coy"/dt - K[COOH" KOH"][C10212 - 2010, I/at 2-[C1021/dt = K[OH")(C10212 -a[C1021/ct - KOHC102) watciog*)/dt = K[CIO)OH)2 Ipts Tries 0/5 For Rate --d[C102/dt, calculate the rate constant (k). (Units required.) 1pts * Tres 0/5 What would be the initial rate (-d[CIO 21/dt) for an experiment with (ClOzlo = 0.210 mol/L and [OH"lo = 0.0866 mol/L? (Units required.) 1pts 122 Tries 0/5

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