Recall that "very satisfied" customers give the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 65 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42. Click here for the Excel Data File (a) Letting / represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis , and the alternative hypothesis ; needed if we wish to attempt to provide evidence supporting the claim that / exceeds 42. HO: H 42 versus Ha: 42 (b) The random sample of 65 satisfaction ratings yields a sample mean of = 42.954. Assuming that o equals 2.64, use critical values to test He Versus ; at each of a = .10, .05, .01, and .001. (Round your answer zog to 3 decimal places and other z-scores to 2 decimal places.) Z = 2.91 Rejection points 20. 10 20.05 20.01 20.001 Reject HO with a = 0. 10, 0.05, 0.01 but not with a = 0.001(c) Using the Information In part (b), calculate the p-value and use it to test we versus #a at each of of = 10, .05, 01, and .001. (Round your answers to 4 decimal places.) p-value = Since p-value = Is less than 0.10. 0.05, 0.01 : reject HO at those levels of a but not with a = 0.001 (d) How much evidence is there that the mean composite satisfaction rating exceeds 42? There is very strong evidence