! Required information One cubic meter of argon is taken from 1 bar and 25C to 10 bar and 307C by the following two-step paths. For the following path, compute Q, W, AU, and AH for each step and for the overall process. Assume mechanical reversibility and treat argon as an ideal gas with Cp=(5/2)R and CV= (3/2) R. The values of Rare given in the following table: Values of the Universal Gas Constant R. = 8.314 J.mol-1 K-1 = 8.314 m.Pa.mol-1.K-1 83.14 cm-bar-mol-1K-1 = 8314 cmkPa.mol-1.K-1 82.06 cm" (atm)-mol-'K-1 = 62,356 cm". (torr) mol-K-1 1.987 (cal) mol K-1 = 1.986 (Btu) (lb mole) (R)-I 0.7302 (ft)' (atm) (lb mol) (R)-' = 10.73 (ft)' (psia) (lb mol)-'(R)-1 1545 (ft) (Ibe) (lb mol) (R)-1 -1 3:50:07 Isothermal compression followed by isobaric heating Book For isothermal compression, rint NU J.mol-1 Q=- J-mol-1, w= J.mol-1 and AH = J.mol-1 rences For isobaric heating, AU= J.mol? Q = J.mol-1, w=- J.mol-1, and AH= J.mol-1 For the overall process, AU= J.mol?, Q= J.mol-1, w= J.mol, and AH= J-mol-1 Adiabatic compression followed by isobaric heating or cooling For adiabatic compression, AU= J.mol-?, Q= J.mol?, w= J.mor!, and AH = J.mol-1 For isobaric heating, U = - J.mol-?, Q=- 7J mol?, W=0 J.mol-1 , and AH=- 7 J-mol-? For the overall process, U = J.mol-1, Q=- J.mol-?, w= J.mol) , and AH= J-mol-1 21 Consider adiabatic compression followed by isochoric heating or cooling. For adiabatic compression, J.mol-? Q J.mol-, w= J.moll, and AH = AU= J.mol-1 ces For isochoric heating, J.mol? Q=- AU= - J.mol-?, W= J.mol-1, and AH=- J.mol-? For the overall process, AU= J.mol-?, Q. =- Jmol? W= J.moll, and AH= J.mol-1