SE Clothing advertises its new brand of shirts on the Internet. Based on large amounts of data on past purchasing experience, the probability distribution of the number of shirts ordered per household generated by this promotional campaign was determined and is tabulated below:

No per household (X)	Probability F(x)
0	0.8
1	0.08
2	0.06
3	0.04
4	0.02

Mean = 0.40

Standard deviation = 0.92

There are 200,000 households in Sea End's customer data base. The orders from household to household are independent of each other.

What is the mean and standard deviation of the number of orders of at least one shirt that SE will realize?